TA có: \(\frac26+\frac{2}{12}+\cdots+\frac{2}{x\left(x+1\right)}=\frac45\)
=>\(\frac{2}{2\cdot3}+\frac{2}{3\cdot4}+\cdots+\frac{2}{x\left(x+1\right)}=\frac45\)
=>\(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\ldots+\frac{1}{x\left(x+1\right)}=\frac25\)
=>\(\frac12-\frac13+\frac13-\frac14+\cdots+\frac{1}{x}-\frac{1}{x+1}=\frac25\)
=>\(\frac12-\frac{1}{x+1}=\frac25\)
=>\(\frac{1}{x+1}=\frac12-\frac25=\frac{5-4}{10}=\frac{1}{10}\)
=>x+1=10
=>x=9