\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{17.19}\)
= \(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{17}-\frac{1}{19}\)
= \(\frac{1}{3}-\frac{1}{19}\)
= \(\frac{16}{57}\)
\(\frac{2}{3.5}+\frac{2}{5.7}+.....+\frac{2}{17.19}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+.....+\frac{1}{17}-\frac{1}{19}\)
\(=\frac{1}{3}-\frac{1}{19}\)
\(=\frac{19}{57}-\frac{3}{57}\)
\(=\frac{16}{57}\)
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Trả lời
1/3-1/9=16/57
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học tốt
\(\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{17.19}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{17}\)\(-\frac{1}{19}\)
\(=\frac{1}{3}-\frac{1}{19}=\frac{16}{57}\)