Question

(2^3.x-4^2).(x-2^2)=0

Answer 1

\(\left(2^3\cdot x-4^2\right)\left(x-2^2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2^3\cdot x-4^2=0\\x-2^2=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}8\cdot x=16\\x=2^2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{16}{8}=2\\x=4\end{matrix}\right.\)

Answer 2

(23⋅x−42)(x−22)=0

⇒[23⋅�−42=0�−22=0⇒[23⋅x−42=0x−22=0​

⇒[8⋅�=16�=22⇒[8⋅x=16x=22​

⇒[�=168=2�=4⇒[x=816​=2x=4​
 

Answer 3

Sửa đề: \(\left(2^3x-4^2\right)\left(x-2\right)^2=0\)

Ta có: \(\left(2^3x-4^2\right)\left(x-2\right)^2=0\)

=>\(\left(8x-16\right)\cdot\left(x-2\right)^2=0\)

=>\(8\left(x-2\right)^3=0\)

=>\(\left(x-2\right)^3=0\)

=>x-2=0

=>x=2