\(2+\dfrac{3}{4}\\ =\dfrac{8}{4}+\dfrac{3}{4}\\ =\dfrac{8+3}{4}\\ =\dfrac{11}{4}\)
\(2+\dfrac{3}{4}\\ =\dfrac{8}{4}+\dfrac{3}{4}\\ =\dfrac{8+3}{4}\\ =\dfrac{11}{4}\)
1, ( -2/5 + 3/10 ) : ( 2/-5 + |-4/3 - 2| )
2, 12,5 . -5/7 + 9 3/4 - 1,5 . 5/7
3, -1/4 . -5/13 - 5/4 . -7/13 + 1/1,3
4, ( -3/4 + 5/13 ) : 2/7 - ( 2 1/4 + 8/13 ) : 2/7
5, ( 3 - 3/4 + 2/3 ) - ( 2 - 4/3 - 3/2 ) - ( 1 - 7/3 - 9/2 )
6, -1/3 - 8/35 + -2/9 - 1/135 z+ 4/5 + -4/9 + 3/7
(3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
(5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 )
mọi người ơi giúp mik với ạ
Tính giá trị các biểu thức sau và viết kết quả dưới dạng bình phương của 1 số
A = 2^5 x (-5)^2 - 8^2 - 7
B = 2^3 x (-4)^2 + (-3)^2 x 3^2 - 40
C= (1/4 - 1/2 - 1) ^3 x (2 - 2/5)^3
D = ( -1/4)^2 : (1/2 - 1/3)
E= 4 x (1/4)^2 + 25 x [(3/4)^3 : (5/4)^3] : (3/2)^3
F = 2^3 + 3 x (1/2)^0 - 1+[(-2)^2 : 1/2] - 8
1 ;(3/7+1/2)^2
2; (3/4-5/6)^2
3; (1+2/3-1/4).(4/5-3/4)^2
4 ,2:(1/2-2/3)^3
\(\frac{\frac{-2}{3}+\frac{3}{4}-2}{\frac{2}{3}-\frac{3}{4}+2}-\frac{\frac{-2}{3}-\frac{3}{4}-2}{\frac{2}{3}+\frac{2}{4}+2}\)
a,(3/7+1/2)2 b, (3/4-5/6)2 c,54.204 /255.45 d,(-105/3).(-64/5)
e,(1+2/3-1/4).(4/5-3/4)2 f 2:(1/2-2/3)3
Tính
\(\frac{-\frac{2}{3}+\frac{3}{4}-2}{\frac{2}{3}-\frac{3}{4}-2}\cdot\frac{-\frac{2}{3}-\frac{3}{4}-2}{\frac{2}{3}+\frac{3}{4}+2}\)
Tính:
a. 4×(1/4)^2+25×[(3/4)^3:(5/4)^3] : (3/2)^3
b. 2^3+3×(1/2)^0-1+[(-2)^2:1/2] - 8
1-1/2+2-2/3+3-3/4+4-1/4-3-1/3-2