\(1\dfrac{1}{6}.2^2-0,5:\dfrac{3}{10}+\dfrac{1}{3}\)
\(=\dfrac{7}{6}.4-\dfrac{1}{2}.\dfrac{10}{3}+\dfrac{1}{3}\)
\(=\dfrac{7}{3}.2-\dfrac{1}{1}.\dfrac{5}{3}+\dfrac{1}{3}\)
\(=\dfrac{14}{3}-\dfrac{5}{3}+\dfrac{1}{3}\)
\(=\dfrac{14-5+1}{3}\)
\(=\dfrac{10}{3}\)