\(15x^2+30=0\\ \Rightarrow x^2+2=0\left(vô.lí\right)\\ \Rightarrow x\in\varnothing\)
\(\left(2x-1\right)^2.4=1\\ \Rightarrow\left(2x-1\right)^2=\dfrac{1}{4}\\ \Rightarrow\left[{}\begin{matrix}2x-1=\dfrac{1}{2}\\2x-1=-\dfrac{1}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{1}{4}\end{matrix}\right.\)