Question

(1+3/4+3/8)^2 -(2+7/8)

Answer 1

\(\left(1+\dfrac{3}{4}+\dfrac{3}{8}\right)^2-\left(2+\dfrac{7}{8}\right)\)

\(=\left(\dfrac{8}{8}+\dfrac{6}{8}+\dfrac{3}{8}\right)^2-\left(\dfrac{16}{8}+\dfrac{7}{8}\right)\)

\(=\left(\dfrac{17}{8}\right)^2-\dfrac{23}{8}\)

\(=\dfrac{289}{64}-\dfrac{184}{64}\)

\(=\dfrac{105}{64}\)

#\(Toru\)

Answer 2

\(\left(1+\dfrac{3}{4}+\dfrac{3}{8}\right)^2-\left(2+\dfrac{7}{8}\right)\)

\(=\left(\dfrac{8}{8}+\dfrac{6}{8}+\dfrac{3}{8}\right)^2-\left(\dfrac{16}{8}+\dfrac{7}{8}\right)\)

\(=\left(\dfrac{8+6+3}{8}\right)^2-\dfrac{16+7}{8}\)

\(=\left(\dfrac{17}{8}\right)^2-\dfrac{23}{8}\)

\(=\dfrac{289}{64}-\dfrac{23}{8}\)

\(=\dfrac{105}{64}\)

Answer 3

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