`@` `\text {Ans}`
`\downarrow`
`16/5 - x = 4/5 - 3/10`
`=> 16/5 - x = 1/2`
`=> x = 16/5 - 1/2`
`=> x = 27/10`
Vậy, `x = 27/10.`
\(\dfrac{1}{20}-\left(x-\dfrac{8}{5}\right)=\dfrac{1}{10}\)
\(\Rightarrow\dfrac{1}{20}-x+\dfrac{8}{5}=\dfrac{1}{10}\)
\(\Rightarrow\dfrac{33}{20}-x=\dfrac{1}{10}\)
\(\Rightarrow x=\dfrac{33}{20}-\dfrac{1}{10}\)
\(\Rightarrow x=\dfrac{31}{20}\)
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\(\dfrac{16}{5}-x=\dfrac{4}{5}-\dfrac{3}{10}\)
\(\Rightarrow\dfrac{16}{5}-x=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{16}{5}-\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{27}{10}\)
a) \(\dfrac{1}{20}-\left(x-\dfrac{8}{5}\right)=\dfrac{1}{10}\)
\(x-\dfrac{8}{5}=\dfrac{1}{20}-\dfrac{1}{10}=-\dfrac{1}{20}\)
\(x=-\dfrac{1}{20}+\dfrac{8}{5}=-\dfrac{1}{20}+\dfrac{32}{20}=\dfrac{31}{20}\)
b) \(\dfrac{16}{5}-x=\dfrac{4}{5}-\dfrac{3}{10}\)
\(x=\dfrac{16}{5}-\dfrac{4}{5}+\dfrac{3}{10}=\dfrac{12}{5}+\dfrac{3}{10}=\dfrac{24}{10}+\dfrac{3}{10}=\dfrac{27}{10}\)
\(\text{∘ Ans}\)
\(\downarrow\)
Mình bổ sung thêm
\(\dfrac{1}{20}-\left\{x-\dfrac{8}{5}\right\}=\dfrac{1}{10}\)
\(\Rightarrow x-\dfrac{8}{5}=\dfrac{1}{20}-\dfrac{1}{10}\)
\(\Rightarrow x-\dfrac{8}{5}=-\dfrac{1}{20}\)
\(\Rightarrow x=-\dfrac{1}{20}+\dfrac{8}{5}\)
\(\Rightarrow x=\dfrac{31}{20}\)
Vậy, \(x=\dfrac{31}{20}\)\(.\)