Ta có: 6x = 4y => x/4 = y/6
4y = 3z => y/3 = z/4 => y/6 = z/8
=> x/4 = y/6 = z/8
Đặt \(\frac{x}{4}=\frac{y}{6}=\frac{z}{8}=k\) => x = 4k; y = 6k; z = 8k
Khi đó, ta có:
M = \(\frac{2.\left(4k\right)^2+5.\left(6k\right)^2-4.\left(8k\right)^2}{7.\left(4k\right)^2-4.\left(6k\right)^2+3.\left(8k\right)^2}\)
= \(\frac{2.4^2.k^2+5.6^2.k^2-4.8^2.k^2}{7.4^2.k^2-4.6^2.k^2+3.8^2.k^2}\)
= \(\frac{k^2.\left(2.16+5.36-4.64\right)}{k^2.\left(7.16-4.36+3.64\right)}\)
= \(\frac{32+180-256}{112-144+194}\)
= \(\frac{-44}{162}=-\frac{22}{81}\)
Đặt \(6x=4y=3z=k\Rightarrow\hept{\begin{cases}x=\frac{k}{6}\\y=\frac{k}{4}\\z=\frac{k}{3}\end{cases}}\) (nhớ đk: x,y,z khác 0 tức là k khác 0)
Thay vào M rồi tự tính.
