\(3x-11\le0\Leftrightarrow x\le\dfrac{11}{3}\Leftrightarrow x\in\left\{1;2;3\right\}\left(x\in N\right)\)
\(\Rightarrow A=\left\{1;2;3\right\}\)
\(\)\(3x^2-14x+11=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{3}\\x=1\end{matrix}\right.\)
\(\Rightarrow B=\left\{1\right\}\left(x\in Z\right)\)
\(A\cup B=\left\{1;2;3\right\}\)
\(A\)\\(B=\left\{2;3\right\}\)
\(B\)\\(A=\varnothing\)