1) Ta có: \(\dfrac{3x+7}{11}=\dfrac{5x-7}{9}\)
\(\Leftrightarrow9\left(3x+7\right)=11\left(5x-7\right)\)
\(\Leftrightarrow27x+63=55x-77\)
\(\Leftrightarrow27x-55x=-77-63\)
\(\Leftrightarrow-28x=-140\)
hay x=5
Vậy: S={5}
1, 3x+7/11= 5x-7/9
3x-5x=-7/11-7/9
-2x=-140/99
x= 70/99
vậy ...
2, x-7/4=9/-7+x
x-x=7/4-9/7
x không có gt thỏa mãn
3, x-1/-2=8/1-x
x+x =-1/2+8/1
2x =15/2
x =15/4
vậy ...