a: ĐKXĐ: x<>5
\(\frac{4x-3}{x-5}=\frac{29}{3}\)
=>3(4x-3)=29(x-5)
=>29x-145=12x-9
=>17x=-9+145=136
=>x=8(nhận)
b: ĐKXĐ: x<>5/3
\(\frac{2x-1}{5-3x}=2\)
=>2(5-3x)=2x-1
=>10-6x=2x-1
=>-8x=-11
=>\(x=\frac{11}{8}\) (nhận)
c: ĐKXĐ: x<>1
\(\frac{4x-5}{x-1}=2+\frac{x}{x-1}\)
=>\(\frac{4x-5}{x-1}=\frac{2x-2+x}{x-1}=\frac{3x-2}{x-1}\)
=>4x-5=3x-2
=>4x-3x=-2+5
=>x=3(nhận)
d: ĐKXĐ: x∉{-2;5}
\(\frac{7}{x+2}=\frac{3}{x-5}\)
=>7(x-5)=3(x+2)
=>7x-35=3x+6
=>4x=41
=>x=41/4(nhận)
e: ĐKXĐ: x∉{0;-5}
\(\frac{2x+5}{2x}-\frac{x}{x+5}=0\)
=>\(\frac{\left(2x+5\right)\left(x+5\right)-2x^2}{2x\left(x+5\right)}=0\)
=>\(\left(2x+5\right)\left(x+5\right)-2x^2=0\)
=>\(2x^2+10x+5x+25-2x^2=0\)
=>15x=-25
=>\(x=-\frac53\) (nhận)
f: ĐKXĐ: x<>4/11
\(\frac{12x+1}{11x-4}+\frac{10x-4}{9}=\frac{20x+17}{18}\)
=>\(\frac{12x+1}{11x-4}=\frac{20x+17}{18}-\frac{10x-4}{9}=\frac{20x+17-20x+8}{18}=\frac{25}{18}\)
=>25(11x-4)=18(12x+1)
=>275x-100=216x+18
=>59x=118
=>x=2(nhận)
