a: \(A=\frac{\left(x-3\right)\left(2y-x\right)}{\left(x-2y\right)^2}\)
\(=\frac{-\left(x-3\right)\left(x-2y\right)}{\left(x-2y\right)^2}=\frac{-\left(x-3\right)}{x-2y}\)
b: \(B=\frac{9x^2-24x+16}{16-9x^2}\)
\(=\frac{\left(3x-4\right)^2}{\left(4-3x\right)\left(4+3x\right)}\)
\(=\frac{\left(4-3x\right)^2}{\left(4-3x\right)\left(4+3x\right)}=\frac{4-3x}{4+3x}\)
c: \(C=\frac{x^3+64}{\left(3-x\right)\cdot\left(x^2-4x+16\right)}\)
\(=\frac{\left(x+4\right)\left(x^2-4x+16\right)}{\left(3-x\right)\left(x^2-4x+16\right)}=\frac{x+4}{3-x}\)
d: \(D=\frac{2x^2-7x+6}{x^2-7x+10}\)
\(=\frac{2x^2-3x-4x+6}{x^2-2x-5x+10}=\frac{x\left(2x-3\right)-2\left(2x-3\right)}{x\left(x-2\right)-5\left(x-2\right)}\)
\(=\frac{\left.\left(x-2\right)\left(2x-3\right)\right.}{\left(x-2\right)\left(x-5\right)}=\frac{2x-3}{x-5}\)
