Question

Answer 1

ĐKXĐ: \(4x^2-12x+9\ge0\)

=>\(\left(2x-3\right)^2\ge0\) (luôn đúng)

=>x∈R

\(\sqrt{4x^2-12x+9}-5=0\)

=>\(\sqrt{\left(2x-3\right)^2}-5=0\)

=>|2x-3|-5=0

=>|2x-3|=5

=>\(\left[\begin{array}{l}2x-3=5\\ 2x-3=-5\end{array}\right.\Rightarrow\left[\begin{array}{l}2x=8\\ 2x=-2\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4\left(nhận\right)\\ x=-1\left(nhận\right)\end{array}\right.\)