a: \(\text{Δ}=\left(-2\right)^2-4\cdot1\cdot\left(-m^2\right)=4m^2+4>=4>0\forall m\)
=>Phương trình luôn có hai nghiệm phân biệt
b: Theo Vi-et, ta có:
\(\left\{{}\begin{matrix}x_1+x_2=-\dfrac{b}{a}=2\\x_1x_2=\dfrac{c}{a}=-m^2\end{matrix}\right.\)
\(\left(x_1+1\right)\left(x_2+1\right)=-3\)
=>\(x_1x_2+\left(x_1+x_2\right)+1=-3\)
=>\(-m^2+2+1=-3\)
=>\(-m^2=-6\)
=>\(m^2=6\)
=>\(m=\pm\sqrt{6}\)