a: ta có: a\(\perp\)c
b\(\perp\)c
Do đó: a//b
b:
Ta có: \(\widehat{D_1}=\widehat{D_2}\)(hai góc đối đỉnh)
mà \(\widehat{D_1}=130^0\)
nên \(\widehat{D_2}=130^0\)
a//b
=>\(\widehat{D_1}=\widehat{C_1}\)(hai góc so le trong)
=>\(\widehat{C_1}=130^0\)
Ta có: \(\widehat{C_1}+\widehat{C_2}=180^0\)(hai góc kề bù)
=>\(\widehat{C_2}=180^0-130^0=50^0\)
