Qua O, kẻ tia OC nằm giữa hai tia OA và OB sao cho OC//a'a//bb'
Ta có: OC//a'a
=>\(\widehat{COA}=\widehat{a'AO}\)(hai góc so le trong)
=>\(\widehat{COA}=30^0\)
Ta có: OC//bb'
=>\(\widehat{COB}=\widehat{OBb'}\)(hai góc so le trong)
=>\(\widehat{COB}=45^0\)
\(\widehat{AOB}=\widehat{AOC}+\widehat{BOC}=30^0+45^0=75^0\)
