1: ĐKXĐ: x>=3
\(\sqrt{4\left(x-3\right)}+\sqrt{9x-27}=10\)
=>\(2\sqrt{x-3}+3\sqrt{x-3}=10\)
=>\(5\sqrt{x-3}=10\)
=>\(\sqrt{x-3}=10\)
=>\(x-3=10^2=100\)
=>x=100+3=103(nhận)
2: ĐKXĐ: x>=-1
\(\sqrt{16x+16}-\sqrt{9x+9}=1\)
=>\(4\sqrt{x+1}-3\sqrt{x+1}=1\)
=>\(\sqrt{x+1}=1\)
=>x+1=1
=>x=0(nhận)
3: ĐKXĐ: x>=2
\(\sqrt{4x-8}=6-\sqrt{x-2}\)
=>\(2\sqrt{x-2}=6-\sqrt{x-2}\)
=>\(3\sqrt{x-2}=6\)
=>\(\sqrt{x-2}=2\)
=>\(x-2=2^2=4\)
=>x=4+2=6(nhận)
4: ĐKXĐ: x>=3
\(\sqrt{4x-12}=10-\sqrt{9x-27}\)
=>\(2\sqrt{x-3}+3\sqrt{x-3}=10\)
=>\(5\sqrt{x-3}=10\)
=>\(\sqrt{x-3}=2\)
=>\(x-3=2^2=4\)
=>x=4+3=7(nhận)