a: Để A có nghĩa thì \(\left\{{}\begin{matrix}x-2>=0\\\sqrt{x-2}-1< >0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=2\\x\ne3\end{matrix}\right.\)
b: \(A^2=\dfrac{x-1-2\sqrt{x-2}}{\left(\sqrt{x-2}-1\right)^2}=\dfrac{x-2-2\sqrt{x-2}+1}{\left(\sqrt{x-2}-1\right)^2}\)
\(=\dfrac{\left(\sqrt{x-2}-1\right)^2}{\left(\sqrt{x-2}-1\right)^2}=1\)
=>\(A=\pm1\)