\(\left(x-\dfrac{1}{3}\right)^3=\dfrac{8}{27}\\ =>\left(x-\dfrac{1}{3}\right)^3=\left(\dfrac{2}{3}\right)^3\\ =>x-\dfrac{1}{3}=\dfrac{2}{3}\\ =>x=\dfrac{2}{3}+\dfrac{1}{3}\\ =>x=\dfrac{3}{3}\\ =>x=1\)
Vậy: ..
`(x-1/3)^3 = 8/27`
`=> (x-1/3)^3= (2/3)^3`
`=>x - 1/3 = 2/3`
`=> x = 2/3 + 1/3 = 3/3 = 1`