\(a.-5x-\dfrac{3}{4}=\dfrac{6}{5}\\ =>5x=-\dfrac{3}{4}-\dfrac{6}{5}\\ =>5x=\dfrac{-39}{20}\\ =>x=\dfrac{-39}{20}:5=-\dfrac{39}{100}\\ b.\dfrac{6}{7}+\dfrac{1}{7}x=\dfrac{-2}{3}\\ =>\dfrac{1}{7}x=\dfrac{-2}{3}-\dfrac{6}{7}\\ =>\dfrac{1}{7}x=\dfrac{-32}{21}\\ =>x=\dfrac{-32}{21}:\dfrac{1}{7}\\ =>x=\dfrac{-32}{3}\\ c.\dfrac{3}{4}-\dfrac{5}{6}x=2-\dfrac{2}{3}\\ =>\dfrac{3}{4}-\dfrac{5}{6}x=\dfrac{4}{3}\\ =>\dfrac{5}{6}x=\dfrac{3}{4}-\dfrac{4}{3}=\dfrac{-7}{12}\\ =>x=-\dfrac{7}{12}:\dfrac{5}{6}=-\dfrac{7}{10}\\ d.2x-\dfrac{2}{3}-7x=\dfrac{3}{2}-1\\ =>\left(2x-7x\right)-\dfrac{2}{3}=\dfrac{1}{2}\\ =>-5x-\dfrac{2}{3}=\dfrac{1}{2}\\ =>-5x=\dfrac{1}{2}+\dfrac{2}{3}=\dfrac{7}{6}\\ =>x=\dfrac{7}{6}:-5=-\dfrac{7}{30}\\ e.\dfrac{1}{2}\left(x+2\right)-4\left(x-\dfrac{1}{4}\right)=\dfrac{1}{2}x\)
\(=>\dfrac{1}{2}x+1-4x+1=\dfrac{1}{2}x\\ =>-4x+2=0\\ =>4x=2\\ =>x=\dfrac{2}{4}=\dfrac{1}{2}\)
a: \(-5x-\dfrac{3}{4}=\dfrac{6}{5}\)
=>\(-5x=\dfrac{3}{4}+\dfrac{6}{5}=\dfrac{15}{20}+\dfrac{24}{20}=\dfrac{39}{20}\)
=>\(x=\dfrac{39}{20}:\left(-5\right)=-\dfrac{39}{100}\)
b: \(\dfrac{6}{7}+\dfrac{1}{7}x=-\dfrac{2}{3}\)
=>\(\dfrac{1}{7}x=-\dfrac{2}{3}-\dfrac{6}{7}=-\dfrac{14}{21}-\dfrac{18}{21}=-\dfrac{32}{21}\)
=>\(x=-\dfrac{32}{21}\cdot7=-\dfrac{32}{3}\)
c: \(\dfrac{3}{4}-\dfrac{5}{6}x=2-\dfrac{2}{3}\)
=>\(\dfrac{3}{4}-\dfrac{5}{6}x=\dfrac{4}{3}\)
=>\(\dfrac{5}{6}x=\dfrac{3}{4}-\dfrac{4}{3}=\dfrac{9}{12}-\dfrac{16}{12}=-\dfrac{7}{12}\)
=>\(x=-\dfrac{7}{12}:\dfrac{5}{6}=-\dfrac{7}{12}\cdot\dfrac{6}{5}=-\dfrac{7}{10}\)
d: \(2x-\dfrac{2}{3}-7x=\dfrac{3}{2}-1\)
=>\(-5x=\dfrac{1}{2}+\dfrac{2}{3}\)
=>\(-5x=\dfrac{3}{6}+\dfrac{4}{6}=\dfrac{7}{6}\)
=>\(x=\dfrac{7}{6}:\left(-5\right)=-\dfrac{7}{30}\)
e: \(\dfrac{1}{2}\left(x+2\right)-4\left(x-\dfrac{1}{4}\right)=\dfrac{1}{2}x\)
=>\(\dfrac{1}{2}x+1-4x+1=\dfrac{1}{2}x\)
=>-4x+2=0
=>-4x=-2
=>\(x=\dfrac{1}{2}\)
