\(\dfrac{6x-1}{3x+2}=\dfrac{2x+5}{x-3}\\ \Leftrightarrow\left(x-3\right)\left(6x-1\right)=\left(2x+5\right)\left(3x+2\right)\\ \Leftrightarrow6x^2-x-18x+3=6x^2+4x+15x+10\\ \Leftrightarrow\left(6x^2-6x^2\right)+\left(-19x-19x\right)+3-10=0\\ \Leftrightarrow-38x-7=0\\ \Leftrightarrow x=-\dfrac{7}{38}\)

