\(\dfrac{7}{9}< \dfrac{7}{5}\)
=>\(-\dfrac{7}{9}>-\dfrac{7}{5}\)
=>\(-\dfrac{7}{5}< -\dfrac{7}{9}< 0\)
\(\dfrac{-4}{-5}=\dfrac{4}{5}=\dfrac{4\cdot11}{5\cdot11}=\dfrac{44}{55};\dfrac{9}{11}=\dfrac{9\cdot5}{11\cdot5}=\dfrac{45}{55}\)
mà 44<45
nên \(\dfrac{-4}{-5}< \dfrac{9}{11}< 1\)
mà \(1< \dfrac{3}{2}\)
nên \(\dfrac{-4}{-5}< \dfrac{9}{11}< \dfrac{3}{2}\)
mà \(0< -\dfrac{4}{-5}\)
nên \(0< \dfrac{-4}{-5}< \dfrac{9}{11}< \dfrac{3}{2}\)
=>\(\dfrac{-7}{5}< \dfrac{-7}{9}< 0< \dfrac{-4}{-5}< \dfrac{9}{11}< \dfrac{3}{2}\)
Ta thấy :
\(\dfrac{7}{9}< \dfrac{7}{5}\Rightarrow\dfrac{-7}{9}>\dfrac{-7}{5}\)
\(\dfrac{-4}{-5}=\dfrac{4}{5}=\dfrac{44}{55}< 1\)
mà \(\dfrac{9}{11}=\dfrac{45}{55}>\dfrac{44}{55}\)
\(\Rightarrow\dfrac{-4}{-5}< \dfrac{9}{11}< 1\)
\(\dfrac{3}{2}>1>0\)
Vậy \(\dfrac{-7}{5}< \dfrac{-7}{9}< 0< \dfrac{-4}{-5}< \dfrac{9}{11}< \dfrac{3}{2}\)
