Question

Answer 1

\(2A-B=2\left(3b+c-2a\right)-\left(-4a+b-3c\right)\\ =6b+2c-4a+4a-b+3c\\ =\left(-4a+4a\right)+\left(6b-b\right)+\left(2c+3c\right)\\ =0+5b+5c\\ =5\left(b+c\right)\)

Answer 2

2A - B

= 2.(3b + c - 2a) - (-4a + b - 3c)

= 6b + 2c - 4a + 4a - b + 3c

= (-4a + 4a) + (6b - b) + (2c + 3c)

= 5b + 5c

= 5(b + c)