Question

Answer 1

2: \(3x^2+y-3x=xy-2\)

=>\(\left(3x^2-3x\right)-\left(xy-y\right)=-2\)

=>\(3x\left(x-1\right)-y\left(x-1\right)=-2\)

=>\(\left(x-1\right)\left(3x-y\right)=-2\)

=>\(\left(x-1;3x-y\right)\in\left\{\left(1;-2\right);\left(-1;2\right);\left(-2;1\right);\left(2;-1\right)\right\}\)

=>\(\left(x;3x-y\right)\in\left\{\left(2;-2\right);\left(0;2\right);\left(-1;1\right);\left(3;-1\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(2;8\right);\left(0;-2\right);\left(-1;-4\right);\left(3;10\right)\right\}\)