1:
AB//CD
=>\(\widehat{BDf}+\widehat{cBD}=180^0\)(hai góc trong cùng phía)
=>\(\widehat{fDB}=180^0-75^0=105^0\)
2:
AD\(\perp\)AB
BC\(\perp\)AB
Do đó: AD//BC
=>\(\widehat{ADC}=\widehat{yCD}\)(hai góc so le trong)
mà \(\widehat{yCD}=70^0\)
nên \(\widehat{ADC}=70^0\)

