Question

Answer 1

\(\left(-\dfrac{3}{2}\right)^{n+2}=\dfrac{729}{64}\)

=>\(\left(-\dfrac{3}{2}\right)^{n+2}=\left(-\dfrac{3}{2}\right)^6\)

=>n+2=6

=>n=4

Answer 2

\(\left(-\dfrac{3}{2}\right)^{n+2}=\dfrac{729}{64}\)

\(\Rightarrow\left(-\dfrac{3}{2}\right)^{n+2}=\left(-\dfrac{3}{2}\right)^6\)

\(\Rightarrow n+2=6\)

\(\Rightarrow n=6-2\)

\(\Rightarrow n=4\)