Question

 

Answer 1

  

Answer 2

a) Ta có : 

\(\left\{{}\begin{matrix}\widehat{xOm}=4x-1\\\widehat{nOx'}=3x-5\end{matrix}\right.\)

mà \(\widehat{xOm}+\widehat{nOx'}+\widehat{mOn}=180^o\) (góc kề bù)

     \(\widehat{mOn}=90^o\)

\(\Rightarrow4x-10+3x+5+90=180\)

\(\Leftrightarrow7x=180-85\)

\(\Leftrightarrow7x=95\)

\(\Leftrightarrow x=13,6^o\)

\(\Rightarrow\left\{{}\begin{matrix}\widehat{xOm}=4.13,6-10=44,4^o\\\widehat{nOx'}=3.13,6-5=35,8^o\end{matrix}\right.\)

Answer 3

Đính chính dòng đầu tiên là \(\widehat{xOm}=4x-10\)