Question

Answer 1

a) \(\left(\dfrac{6}{7}+1\dfrac{1}{2}\right)^2=\left(\dfrac{6}{7}+\dfrac{3}{2}\right)^2=\left(\dfrac{33}{14}\right)^2=\dfrac{1089}{196}\)

b) \(\left(2\dfrac{1}{5}-1\dfrac{2}{3}\right)^3=\left(\dfrac{11}{5}-\dfrac{5}{3}\right)^3=\left(\dfrac{8}{15}\right)^3=\dfrac{512}{3375}\)

c) \(3^2+4.\left(\dfrac{7}{9}\right)^0+\left[\left(-5\right)^2:\dfrac{1}{5}\right]:25\)

\(=9+4+125:25\)

\(=13+5\)

\(=18\)

Answer 2

a: =(6/7+3/2)^2=(33/14)^2=1089/196

b: =(11/5-5/3)^3=(8/15)^3=512/3375

c: =9+4-[25*5]:25

=13-5=8