ĐKXĐ: x<>2; x<>-2
\(\frac{x-1}{x+2}-\frac{x}{x-2}=\frac{3x-2}{4-x^2}\)
=>\(\frac{\left(x-1\right)\left(x-2\right)-x\left(x+2\right)}{\left(x+2\right)\left(x-2\right)}=\frac{-3x+2}{\left(x-2\right)\left(x+2\right)}\)
=>(x-1)(x-2)-x(x+2)=-3x+2
=>\(x^2-3x+2-x^2-2x=-3x+2\)
=>-5x+2=-3x+2
=>-2x=0
=>x=0(nhận)


