Câu 2:
a: ĐKXĐ: x>=0; x<>4
\(P=\dfrac{x-8\sqrt{x}+12+10\sqrt{x}+20-32}{x-4}=\dfrac{x+2\sqrt{x}}{x-4}=\dfrac{\sqrt{x}}{\sqrt{x}-2}\)
b: Để \(\dfrac{P}{\sqrt{x}}=\dfrac{\sqrt{x}}{\sqrt{x}-2}:\sqrt{x}=\dfrac{1}{\sqrt{x}-2}=\dfrac{1}{2}\) thì \(\sqrt{x}-2=2\)
=>x=16

