a: Khi x=9/4 thì B=(3/2-1):(3/2+1)=1/2:5/2=1/5
b: \(A=\dfrac{\sqrt{x}+1+x}{\sqrt{x}\left(\sqrt{x}+1\right)}\cdot\dfrac{x+\sqrt{x}}{\sqrt{x}+2}=\dfrac{x+\sqrt{x}+1}{\sqrt{x}+2}\)
c: Để A=7/3 thì \(\dfrac{x+\sqrt{x}+1}{\sqrt{x}+2}=\dfrac{7}{3}\)
=>3x+3 căn x+3-7 căn x-14=0
=>3x-4 căn x-11=0
=>\(x=\left(\dfrac{2+\sqrt{37}}{3}\right)^2\)

