a: \(A=\dfrac{x-1-4\sqrt{x}+4+1}{x-1}\cdot\dfrac{x-1}{x-2\sqrt{x}}\)
\(=\dfrac{\left(\sqrt{x}-2\right)^2}{\sqrt{x}\left(\sqrt{x}-2\right)}=\dfrac{\sqrt{x}-2}{\sqrt{x}}\)
b: Để A=1/2 thì \(\dfrac{\sqrt{x}-2}{\sqrt{x}}=\dfrac{1}{2}\)
=>2 căn x-4=căn x
=>căn x=4
=>x=16

