b: \(=1-\dfrac{22}{9}\cdot\dfrac{4}{9}=1-\dfrac{88}{81}=\dfrac{-7}{81}\)
\(\left(-\dfrac{1}{7}\right)^0-2\dfrac{4}{9}\cdot\left(\dfrac{2}{3}\right)^2\)
\(=1-\left(2+\dfrac{4}{9}\right)\cdot\dfrac{4}{9}\)
\(=1-\dfrac{22}{9}\cdot\dfrac{4}{9}\)
\(=1-\dfrac{88}{81}=\dfrac{81}{81}-\dfrac{88}{81}=-\dfrac{7}{81}\)