a: \(A=\dfrac{15\sqrt{x}-11-\left(3x+7\sqrt{x}-6\right)-\left(2x-2\sqrt{x}+3\sqrt{x}-3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{-5x+7\sqrt{x}-2}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}=\dfrac{-5\sqrt{x}-2}{\left(\sqrt{x}+3\right)}\)
b: Để |A|=1 thì A=-1 hoặc A=1
=>A=-1(vì A<0)
\(\Leftrightarrow-5\sqrt{x}-2=-\sqrt{x}-3\)
=>4 căn x=1
=>x=1/16

