Question

Answer 1

m: \(=2^{16}\cdot2^{20}=2^{36}\)

k: \(=5^{40}\cdot5^{12}=5^{52}\)

l: \(=4^8\)

Answer 2

\(4^8.2^{20}=2^{2^8}.2^{20}=2^{2.8}.2^{20}=2^{16}.2^{20}=2^{16+20}=2^{36}\)

\(25^{20}.125^4=5^{2^{20}}.5^{3^4}=5^{40}.5^{12}=5^{40+12}=5^{52}\)

\(y.y^7=y^1.y^7=y^{1+7}=y^8\)

\(2^3.2^2.8^3=2^3.2^22^{3^3}=2^3.2^2.2^9=2^{3+2+9}=2^{14}\)