a: A=(x1+x2)^3-3x1x2(x1+x2)
=(2căn3)^3-3*2căn 3*1
=24*căn 3-6*căn 3=18căn 3
b: \(B=\dfrac{3\left[\left(x_1+x_2\right)^2-2x_1x_2\right]+5x_1x_2}{4x_1x_2\left[\left(x_1+x_2\right)^2-2x_1x_2\right]}\)
\(=\dfrac{3\cdot\left[12-2\right]+5}{4\cdot1\cdot\left[12-2\cdot1\right]}\)
=7/8
