Question

Answer 1

\(\dfrac{2\sqrt{3}-3\sqrt{2}}{\sqrt{6}}-\dfrac{2-\sqrt{2}}{1-\sqrt{2}}+\dfrac{3}{\sqrt{3}}\\ =\dfrac{\sqrt{3}.\sqrt{2}.\left(\sqrt{2}-\sqrt{3}\right)}{\sqrt{6}}+\dfrac{\sqrt{2}\left(\sqrt{2}-1\right)}{\sqrt{2}-1}+\dfrac{\sqrt{3}^2}{\sqrt{3}}\\ =\sqrt{2}-\sqrt{3}+\sqrt{2}+\sqrt{3}=2\sqrt{2}\)

Answer 2

\(=\sqrt{2}-\sqrt{3}+\sqrt{2}+\sqrt{3}=2\sqrt{2}\)