c: \(\Leftrightarrow10\sqrt{3x}-4\sqrt{3x}+8\sqrt{3x}=14\)
\(\Leftrightarrow14\sqrt{3x}=14\)
=>3x=1
hay x=1/3
d: \(\Leftrightarrow2\sqrt{x-1}+\dfrac{3}{2}\cdot2\sqrt{x-1}-\dfrac{1}{3}\cdot3\sqrt{x-1}=12\)
\(\Leftrightarrow4\sqrt{x-1}=12\)
=>x-1=9
hay x=10
e: \(\Leftrightarrow\dfrac{2}{5}\cdot5\sqrt{x+1}-3\cdot\sqrt{x+1}+\dfrac{5}{2}\cdot2\sqrt{x+1}=8\)
\(\Leftrightarrow4\sqrt{x+1}=8\)
=>x+1=4
hay x=3
\(c,5\sqrt{12x}-4\sqrt{3x}+2\sqrt{48x}=14\\ 5.2\sqrt{3x}-4\sqrt{3x}+2.4\sqrt{3x}=14\\ 14\sqrt{3x}=14\\ \sqrt{3x}=1\\ 3x=1\\ x=\dfrac{1}{3}\)
\(d,2\sqrt{x-1}+\dfrac{3}{2}\sqrt{4x-4}-\dfrac{1}{3}\sqrt{9x-9}=12\\ 2\sqrt{x-1}+\dfrac{3}{2}.2\sqrt{x-1}-\dfrac{1}{3}.3\sqrt{x-1}=12\\ 4\sqrt{x-1}=12\\ \sqrt{x-1}=3\\ x-1=9\\ x=10\)
\(e,\dfrac{2}{5}\sqrt{25x+25}-3\sqrt{x+1}+\dfrac{5}{2}\sqrt{4x+4}=8\\ \dfrac{2}{5}.5\sqrt{x+1}-3\sqrt{x+1}+\dfrac{5}{2}.2\sqrt{x+1}=8\\ 4\sqrt{x+1}=8\\ \sqrt{x+1}=2\\ x+1=4\\ x=3\)
\(g,3\sqrt{2x}+4\sqrt{8x}-\sqrt{18x}=10\\ 3\sqrt{2x}+4.2\sqrt{2x}-3\sqrt{2x}=10\\ 8\sqrt{2x}=10\\ \sqrt{2x}=\dfrac{5}{4}\\ 2x=\dfrac{25}{16}\\ x=\dfrac{25}{32}\)
\(c,5\sqrt{12x}-4\sqrt{3x}+2\sqrt{48x}=14.\\ \Leftrightarrow10\sqrt{3x}-4\sqrt{3x}+8\sqrt{3x}=14.\\ \Leftrightarrow14\sqrt{3x}=14.\\ \Leftrightarrow\sqrt{3x}=1.\\ \Leftrightarrow3x=1.\\ \Leftrightarrow x=\dfrac{1}{3}.\)
\(d,2\sqrt{x-1}+\dfrac{3}{2}\sqrt{4x-4}-\dfrac{1}{3}\sqrt{9x-9}=12.\\ \Leftrightarrow2\sqrt{x-1}+\dfrac{3}{2}\sqrt{4\left(x-1\right)}-\dfrac{1}{3}\sqrt{9\left(x-1\right)}=12.\\ \Leftrightarrow2\sqrt{x-1}+3\sqrt{x-1}-\sqrt{x-1}=12.\\ \Leftrightarrow4\sqrt{x-1}=12.\\ \Leftrightarrow\sqrt{x-1}=3.\\ \Leftrightarrow x-1=9.\\ \Leftrightarrow x=10.\)
\(e,\dfrac{2}{5}\sqrt{25x+25}-3\sqrt{x+1}+\dfrac{5}{2}\sqrt{4x+4}=8.\\ \Leftrightarrow\dfrac{2}{5}\sqrt{25\left(x+1\right)}-3\sqrt{x+1}+\dfrac{5}{2}\sqrt{4\left(x+1\right)}=8.\\ \Leftrightarrow2\sqrt{x+1}-3\sqrt{x+1}+5\sqrt{x+1}=8.\\ \Leftrightarrow4\sqrt{x+1}=8.\\ \Leftrightarrow\sqrt{x+1}=2.\\ \Leftrightarrow x+1=4.\\ \Leftrightarrow x=3.\)
\(g,3\sqrt{2x}+4\sqrt{8x}-\sqrt{18x}=10.\\ \Leftrightarrow g,3\sqrt{2x}+8\sqrt{2x}-3\sqrt{2x}=10.\\ \Leftrightarrow8\sqrt{2x}=10.\\ \Leftrightarrow\sqrt{2x}=\dfrac{5}{4}.\\ \Leftrightarrow2x=\dfrac{25}{16}.\\ \Leftrightarrow x=\dfrac{25}{32}.\)
