a: \(B=\dfrac{x-2\sqrt{x}+1-3\sqrt{x}-3+7\sqrt{x}+3}{x-1}\)
\(=\dfrac{x+2\sqrt{x}+1}{x-1}=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}\)
b: Thay x=1/4 vào B, ta được:
\(B=\left(\dfrac{1}{2}+1\right):\left(\dfrac{1}{2}-1\right)=\dfrac{3}{2}:\dfrac{-1}{2}=-3\)
c: Để B=4 thì \(\sqrt{x}+1=4\sqrt{x}-4\)
=>\(-3\sqrt{x}=-5\)
hay x=25/9
