Question

Answer 1

1: \(=\sqrt{3}-2-\sqrt{3}=-2\)

2: \(=\sqrt{5}-2+\sqrt{5}+2=2\sqrt{5}\)

3: \(=3-\sqrt{2}+5-\sqrt{2}=8-2\sqrt{2}\)

4: \(=3-\sqrt{3}+2\sqrt{3}-3=\sqrt{3}\)

5: \(=\dfrac{\sqrt{6}-\sqrt{2}}{\sqrt{3}-1}-2\sqrt{2}=\sqrt{2}-2\sqrt{2}=-\sqrt{2}\)

6: \(=\dfrac{4-2\sqrt{3}}{\sqrt{3}-1}=\sqrt{3}-1\)

7: \(=12+6\sqrt{3}+2-\sqrt{3}-5\sqrt{3}=14\)

8: \(=\left(\sqrt{7}+\sqrt{5}\right)\left(\sqrt{7}-\sqrt{5}\right)=7-5=2\)