Ta có: \(P=\frac{x^4+3x^2+4}{x^2+1}\)
\(=\frac{x^4+x^2+2x^2+2+2}{x^2+1}=x^2+2+\frac{2}{x^2+1}\)
\(=x^2+1+\frac{2}{x^2+1}+1\ge2\cdot\sqrt{\left(x^2+1\right)\cdot\frac{2}{x^2+1}}+1=2\sqrt2+1\)
Dấu '=' xảy ra khi \(\left(x^2+1\right)^2=2\)
=>\(x^2+1=\sqrt2\)
=>\(x^2=\sqrt2-1\)
=>\(x=\pm\sqrt{\sqrt2-1}\)

