Question

Answer 1

b: ĐKXĐ: x>=0; x<=100

Ta có: \(\sqrt{15+\sqrt{x}}+\sqrt{10-\sqrt{x}}=7\)

=>\(\sqrt{15+\sqrt{x}}-4+\sqrt{10-\sqrt{x}}-3=0\)

=>\(\frac{15+\sqrt{x}-16}{\sqrt{15+\sqrt{x}}+4}+\frac{10-\sqrt{x}-9}{\sqrt{10-\sqrt{x}}+3}=0\)

=>\(\frac{\sqrt{x}-1}{\sqrt{15+\sqrt{x}}+4}-\frac{\sqrt{x}-1}{\sqrt{10-\sqrt{x}}+3}=0\)

=>\(\sqrt{x}-1=0\)

=>\(\sqrt{x}=1\)

=>x=1(nhận)