Question

Answer 1

a: \(27^{11}=3^{33}\)

\(81^8=3^{32}\)

mà 33>32

nên \(27^{11}>81^8\)

b: \(63^{15}< 64^{15}=2^{90}\)

\(34^{18}>32^{18}=2^{90}\)

Do đó: \(63^{15}< 34^{18}\)

Answer 2

\(a,27^{11}=\left(3^3\right)^{11}=3^{33}\\ 81^8=\left(3^4\right)^8=3^{32}\)

VÌ \(3^{33}>3^{32}\Rightarrow27^{11}>81^8\)

\(b,63^{15}< 64^{15}=\left(2^6\right)^{15}=2^{90}\\ 34^{18}>32^{18}=\left(2^5\right)^{18}=2^{90}\)

\(\Rightarrow63^{15}< 2^{90}< 34^{18}\)