a: Để (d1)//(d2) thì \(\left\{{}\begin{matrix}3m^2+1=4m\\m^2-9< >-m-5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left(3m-1\right)\left(m-1\right)=0\\m^2+m-4< >0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}m=1\\m=\dfrac{1}{3}\end{matrix}\right.\)
b: Để (d1) cắt (d2) thì \(3m^2+1< >4m\)
hay \(m\notin\left\{1;\dfrac{1}{3}\right\}\)
