Question

Answer 1

\(\left(x-3\right)\left(5-2x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-3=0\\5-2x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{5}{2}\end{matrix}\right.\)

Vậy phương trình có tập nghiệm \(S=\left\{3;\dfrac{5}{2}\right\}\)

Answer 2

\(\left(x-3\right)\left(5-2x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\5-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{5}{2}\end{matrix}\right.\)

Answer 3

S={3;5/2}