\(\dfrac{4x+13}{5x\left(x-7\right)}-\dfrac{x-48}{5x\left(7-x\right)}\\ =\dfrac{4x+13}{5x\left(x-7\right)}+\dfrac{x-48}{5x\left(x-7\right)}\\ =\dfrac{4x+13+x-48}{5x\left(x-7\right)}\\ =\dfrac{5x-35}{5x\left(x-7\right)}\\ =\dfrac{5\left(x-7\right)}{5x\left(x-7\right)}\\ =\dfrac{1}{x}\)
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\(=\dfrac{4x+13+x-48}{5x\left(x-7\right)}=\dfrac{5x-35}{5x\left(x-7\right)}=\dfrac{1}{x}\)
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