a: \(Na_2O\)
b: \(Al\left(OH\right)_3\)
d: \(FeSO_4\)
a,\(Na_2O\)
\(PTK_{Na_2O}=23.2+16=62đvC\)
b, \(Al\left(OH\right)_3\)
\(PTK_{Al\left(OH\right)_3}=27+\left(16+1\right).3=78đvC\)\
c, \(FeSO_4\)
\(PTK_{FeSO_4}=56+32+16.4=152đvC\)
\(a,CTHH.chung:Na_xO_y\\ Theo.quy.tắc.hóa.trị:x.I=y.II\\ Chuyển.thành.tỉ.lệ:\dfrac{x}{y}=\dfrac{2}{1}\\ \Rightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\\ CTHH:Na_2O\\ PTK:23.2+16=62\left(đvC\right)\)
\(b,CTHH.chung:Al_x\left(OH\right)_y\\ Theo.quy.tắc.hóa.trị:x.III=y.I\\ Chuyển.thành.tỉ.lệ:\dfrac{x}{y}=\dfrac{1}{3}\\ \Rightarrow\left\{{}\begin{matrix}x=1\\y=3\end{matrix}\right.\\ CTHH:Al\left(OH\right)_3\\ PTK:27+\left(16+1\right).3=78\left(đvC\right)\)
\(c,CTHH.chung:Fe_x\left(SO_4\right)_y\\ Theo.quy.tắc.hóa.trị:x.II=y.II\\ Chuyển.thành.tỉ.lệ:\dfrac{x}{y}=\dfrac{2}{2}=\dfrac{1}{1}\\ \Rightarrow\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\\ CTHH:FeSO_4\\ PTK:56+32+16.4=152\left(đvC\right)\)
