\(\sqrt[3]{27}+\sqrt[3]{64}-\sqrt[3]{125}\)\(=3+4+5=12\)
Câu 1:
\(b,\sqrt[3]{27}+\sqrt[6]{64}-\sqrt[3]{125}=3+4-5=2\)
Câu 2:
\(a,2>0\Rightarrow\) Hàm đồng biến
\(b,\text{Vì }A\left(0;4\right)\in y=2x+b\Leftrightarrow2\cdot0+b=4\Leftrightarrow b=4\)
\(c,A=\left(\sqrt{99}-\sqrt{18}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\\ A=\left(3\sqrt{11}-3\sqrt{2}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\\ A=\left(2\sqrt{11}-3\sqrt{2}\right)\sqrt{11}+3\sqrt{22}=22-3\sqrt{22}+3\sqrt{22}=22\)

