b: \(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{2}{x+y}=\dfrac{1}{4}\\\dfrac{1}{x-y}=\dfrac{1}{x+y}+\dfrac{3}{8}=\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+y=8\\x-y=2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x=10\\x-y=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5\\y=3\end{matrix}\right.\)